Current location - Health Preservation Learning Network - Slimming men and women - As shown in the figure, it is an experimental device for preparing NH3 in the laboratory and testing some of its properties. Complete the following questions; (1) As shown in the figure, the name of i
As shown in the figure, it is an experimental device for preparing NH3 in the laboratory and testing some of its properties. Complete the following questions; (1) As shown in the figure, the name of i
As shown in the figure, it is an experimental device for preparing NH3 in the laboratory and testing some of its properties. Complete the following questions; (1) As shown in the figure, the name of instrument D is _ _ _ _ _ _, (2 (1) As can be seen from the figure, the name of instrument D is round bottom flask.

So the answer is: round bottom flask;

(2) Ammonia salt and alkali react to generate ammonia gas and water. Calcium hydroxide and ammonium chloride react to prepare ammonia under the condition of heating in the laboratory. The chemical equation of the reaction is Ca(OH)2+2NH4Cl? △? . ? CaCl2+2NH3↑+2H2O,

So the answer is: Ca(OH)2+2NH4Cl? △? . ? CaCl 2+2n H3 ↑+ 2H2O;

(3) This experiment is a "fountain experiment" of ammonia. The experimenter uses a dropper to squeeze a small amount of water into a drying container filled with ammonia, and the ammonia dissolves in the water, thus generating negative pressure in the container. Therefore, more water enters from another entrance under the action of atmospheric pressure, resulting in fountain effect, which tests the solubility of ammonia in water.

Therefore, the answer is: ammonia is very soluble in water;

(4)NH3+H2O? NH3? H2O, ammonia exists: NH3? H2O? OH-+NH4+, OH- is ionized, the solution is alkaline, and turns red when it meets phenolphthalein test solution.

So, the answer is: the red fountain can be observed; NH3+H2O? NH3? H2O? OH-+NH4+;

(5) Let ammonia be VL, the amount of ammonia be V22.4mol, and the volume of the solution after the reaction be VL, then the concentration is C = NV = V22.4 mol VL =122.4 mol/L.

So the answer is: 122.4.