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Given a regular triangular pyramid S-ABC, the height SO is equal to a, and the inclined height SM is equal to 2a. Find the lateral area and volume of the pyramid.
Connect AO, OM,

O is the outer center (weight, inner center and vertical center) of positive △ABC,

A, O, M three-point * * * line,

△SOM is RT△,

According to Pythagorean theorem,

OM=√3a,

According to the nature of the center of gravity,

OM=AM/3,

∴AM=3√3a,

BM=√3AM/3=3a,

∴BC=2BM=6a,

∴S△SBC=SM*BC/2=2a*6a/2=6a^2,

∴ lateral area: s side = 3 * 6A 2 = 18A 2.

S△ABC=BC*AM/2=6a*3√3a/2=9√3a^2,

∴vs-abc=s△abc*so/3=9√3a^2*a/3=3√3a^3.