Then the reaction can be seen as two steps.
Step 1: NaOH+CO2=NaHCO3.
Reaction residual NaOH? (9-5=4 copies)
Then the reaction occurs: NaHCO3+NaOH=Na2CO3+H2O.
4 parts of NaHCO3 reacted, leaving (5-4= 1 part) NaHCO3.
The final products are NaHCO3 and Na2CO3, and the ratio is 1: 4.
Can also be written as a general equation:
9NaOH+5CO2=4Na2CO3+NaHCO3+4H2O