The idea is: let length x width Y XY = 3000;; Find the maximum value of Z=2(X+Y)!
That is, (x+y) (x+y) = xx+2xy+YY = xx+YY+6000 = ZZ/4.
(X-Y)(X-Y)=XX-YY=NN
2XX+6000=ZZ/4+NN
2YY+6000=ZZ/4-NN
Where xx < 3000 YY <; 3000
ZZ/4+NN & gt; 12000
ZZ/4-NN & gt; 12000
ZZ & gt24000*4== >ZZ & gt96000 == > The limit value of z can be found.
You can also draw a graph Y=3000/X when X=Y and X+Y is the minimum.
This time it's the square!