( 1)? Velocity images can be represented by S-T images and V-T images. Fig. 1 and fig. 2 are images of uniform linear motion; Figs. 3 and 4 are images of uniformly accelerated linear motion (a variable speed motion) with an initial speed not equal to 0;
(2)? From the image 1, it can be seen that the S-T image with uniform linear motion is a part of the image with a proportional function, and the functional relationship is as follows: S=vt, the velocity v (the slope of the straight line) of the object with uniform linear motion is constant, which has nothing to do with the distance S and time T. Under the condition of constant velocity, the distance S is proportional to the time T;
(3)? As can be seen from Figure 2, the S-V image with uniform linear motion is a part of the image with invariant function, and its functional relationship is: v? =? v？ The velocity v of an object moving in a straight line at a uniform speed is constant, which has nothing to do with the distance s and time t. In a period of time (t), the distance (s) traveled satisfies the relationship: S=vt? That is the area surrounded by a rectangle in the image;
(4)? As can be seen from Figure 3, the S-T image of uniformly accelerated linear motion with initial velocity not 0 is a part of quadratic function image, and its functional relationship is: S=v0t+at? /2? The acceleration a and initial velocity v0 of uniformly accelerated linear motion are constant and have nothing to do with distance s and time t;
(5)? As can be seen from Figure 4, the S-V image of uniformly accelerated linear motion with initial velocity not 0 is a part of linear function image, and its functional relationship is: v=v0+at? The acceleration a (the slope of a straight line) of an object moving at a uniform speed is constant, and the initial velocity v0 is also constant, which has nothing to do with the distance s and time t. In a period of time (t 1), the distance traveled (s) satisfies the relationship: S=v0t 1+at? /2? , the area surrounded by "rectangle+triangle" in the image.
I hope I can help you. You can ask questions ~ ~ ~
I wish you progress in your studies and go up a storey still higher! (*^__^*)?
The attached drawings are as follows: