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How to calculate reinforcement
Question 1: How to calculate the weight of reinforcement? The theoretical weight of reinforcement is calculated by multiplying the square (mm) of reinforcement diameter by 0.006 17.

0.6 17 is the reinforcement weight per meter of circle 10. The weight of steel bars is proportional to the square of the diameter (radius).

G=0.6 17*D*D/ 100

Weight per meter (kg) = rebar diameter (mm)× rebar diameter (mm)×0.006 17.

In fact, it is very simple to remember the weight of steel bars commonly used in construction projects: φ 6 = 0.222kgφ 6.5 = 0.26kgφ 8 = 0.395kg φ10 = 0.617 kgφ12 = 0.888kgφ14 =/kloc. 438+08 = 2.0kgφ24 = 2.47kgφ22 = 2.98kgφ25 = 3.85kgφ28 = 4.837kg ............

Steel bars below φ 12 (including 12) and φ 28 (including 28) generally take three decimal places, and steel bars from φ 14 to φ 25 generally take two decimal places.

φ 6 = 0.222kg.

φ8 = 0.395kg

φ 10 = 0.6 17kg

φ12 = 0.888kg.

φ 14 = 1.2 1kg

φ 16 = 1.58kgφ 18 = 2kg

φ 20 = 2.47kg.

22 = 3Kg

φ 25 = 3.86kg.

I have an empirical formula. Just calculate your own table. You can also buy a book with a watch, which is also very convenient to use.

A simple formula for calculating the theoretical weight of steel

Material Name Theoretical Weight W (kg/m)

Flat steel, steel plate and steel strip w = 0.00785× width× thickness

Square steel w = 0.00785× side length 2

Round steel, steel wire and steel wire w = 0.006 17× diameter 2.

Steel pipe w = 0.02466× wall thickness (outside diameter-wall thickness)

Equiangular W = 0.00785× side thickness (2 side width-side thickness)

Unequal angle steel w = 0.00785× side thickness (long side width+short side width-side thickness)

I-beam w = 0.00785× waist thickness [height +f (leg width-waist thickness)]

Channel steel w = 0.00785× waist thickness [height +e (leg width-waist thickness)]

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The exact calculation formulas of 1, angle steel, I-beam and channel steel are very complicated, so the approximate values are calculated by table simplification.

2.f value: 3.34 for general model and A model, 2.65 for B model and 2.26 for C model. ..

3.e value: 3.26 for general model and A model, 2.44 for B model and 2.24 for C model. ..

4. All length units are millimeters.

Question 2: Calculation method of reinforcement weight 1. Calculate the number of various types of steel bars according to the drawings.

2. You can check the weight per meter of each steel bar (the weight per meter of the first-class steel bar is the same as that of the second-class steel bar and the third-class steel bar). For example, φ 6 rebar is 0.222kg/ m, φ 8 rebar is 0.385kg/ m, φ 10 rebar is 0.6 17kg/ m, φ 12 rebar is 0.888kg/ m, and φ 14 rebar 1 4 rebar.

Question 3: How to calculate the weight of steel bars? Multiply the square of rebar diameter (mm) by 0.006 17.

0.6 17 is the reinforcement weight per meter of circle 10. The weight of steel bars is proportional to the square of the diameter (radius).

G=0.6 17*D*D/ 100

Weight per meter (Kg)= rebar diameter (mm)× rebar diameter (mm)×0.006 17.

In fact, it is very simple to remember the weight of steel bars commonly used in construction projects: φ 6 = 0.222kgφ 6.5 = 0.26kgφ 8 = 0.395kg φ10 = 0.617 kgφ12 = 0.888kgφ14 =/kloc. 438+08 = 2.0kgφ24 = 2.47kgφ22 = 2.98kgφ25 = 3.85kgφ28 = 4.837kg ............

Steel bars below φ 12 (including 12) and φ 28 (including 28) generally take three decimal places, and steel bars from φ 14 to φ 25 generally take two decimal places.

φ 6 = 0.222kg.

φ8 = 0.395kg

φ 10 = 0.6 17kg

φ12 = 0.888kg.

φ 14 = 1.2 1kg

φ 16 = 1.58kg

φ 18 = 2kg

φ 20 = 2.47kg.

22 = 3Kg

φ 25 = 3.86kg.

I have an empirical formula. Just calculate your own table. You can also buy a book with a watch, which is also very convenient to use.

A simple formula for calculating the theoretical weight of steel

Material Name Theoretical Weight W (kg/m)

Flat steel, steel plate and steel strip W=0.00785× width× thickness

Square steel W=0.00785× side length 2

Round steel, steel wire and steel wire W=0.006 17× diameter 2.

Steel pipe W=0.02466× wall thickness (outside diameter-wall thickness)

Equiangular W=0.00785× side thickness (2 side width-side thickness)

Unequal angle steel W=0.00785× side thickness (long side width+short side width-side thickness)

I-beam W=0.00785× waist thickness [height +f (leg width-waist thickness)]

Channel steel W=0.00785× waist thickness [height +e (leg width-waist thickness)]

comment

The exact calculation formulas of 1, angle steel, I-beam and channel steel are very complicated, so the approximate values are calculated by table simplification.

2.f value: 3.34 for general model and A model, 2.65 for B model and 2.26 for C model. ..

3.e value: 3.26 for general model and A model, 2.44 for B model and 2.24 for C model. ..

4. All length units are millimeters.

Question 4: How to calculate the cross-sectional area of steel bar s=π? r2 .

For example, the cross-sectional area of a steel bar with a diameter of 12 is s = 3.1415926×122 = 452.39mm2, which is very simple.

There are tables in Code for Design of Concrete Structures.

Appendix B Nominal cross-sectional area, calculated cross-sectional area and theoretical weight of reinforcement

See table B. 1

Nominal diameter (mm) Calculated cross-sectional area of different numbers of steel bars (mm2) Theoretical weight of single steel bar (kg/m)

1 2 3 4 5 6 7 8 9

6 28.3 57 85 1 13 142 170 198 226 255 0.222

6.5 33.2 66 100 133 166 199 232 265 299 0.260

8 50.3 10 1 15 1 20 1 252 302 352 402 453 0.395

8.2 52.8 106 158 2 1 1 264 3 17 370 423 475 0.432

10 78.5 157 236 3 14 393 47 1 550 628 707 0.6 17

12 1 13. 1 226 339 452 565 678 79 1 904 10 17 0.888

14 153.9 308 46 1 6 15 769 923 1077 123 1 1385 1.2 1

16 20 1. 1 402 603 804 1005 1206 1407 1608 1809 1.58

18 254.5 509 7 to 310/71272152717812036 2290 2.00.

20 3 14.2 628 942 1256 1570 1884 2 199 25 13 2827 2.47

22 380. 1 760 1 140 1520 1900 228 1 266 1 304 1 342 1 2.98

25 490.9 982 1473 1964 2454 2945 3436 3927 44 18 3.85

28 6 15.8 1232 1847 2463 3079 3695 43 10 4926 5542 4.83

32 804.2 1609 24 13 32 17 402 1 4826 5630 6434 7238 6.3 1

36 10 17.9 2036 3054 4072 5089 6 107 7 125 8 143 9 16 1 7.99

40 1256.6 25 13 3770 5027 6283 7540 8796 10053 1 13 10 9.87

50 1964 3928 5892 7856 9820 1 1784 13748 157 12 17676 15.42

Question 5: How to calculate the theoretical weight of rebar with rebar diameter d = D2/100 * 0.617 = D2× 0.0017?

2 is the square, and 0.6 17 is the theoretical weight of steel bars with a diameter of 10. Just remember the theoretical weight of reinforcement 10!

Three decimal places are reserved for the diameter of 12 and below; If the diameter is more than 12, two decimal places shall be reserved; When you keep it, 6 homes and 7 entrances!

Multiplying the square (mm) of rebar diameter by 0.006 17 0.6 17 is the weight circle of rebar per meter 10. The weight of steel bars is proportional to the square of the diameter (radius).

G=0.6 17*D*D/ 100

Weight per meter (kg) = rebar diameter (mm)× rebar diameter (mm)×0.006 17.

In fact, it is very simple to remember the weight of steel bars commonly used in construction projects: φ 6 = 0.222kgφ 6.5 = 0.26kgφ 8 = 0.395kg φ10 = 0.617 kgφ12 = 0.888kgφ14 =/kloc. 438+08 = 2.0kgφ24 = 2.47kgφ22 = 2.98kgφ25 = 3.85kgφ28 = 4.837kg ............

Steel bars below φ 12 (including 12) and φ 28 (including 28) generally take three decimal places, and steel bars from φ 14 to φ 25 generally take two decimal places.

φ 6 = 0.222kg.

φ8 = 0.395kg

φ 10 = 0.6 17kg

φ12 = 0.888kg.

φ 14 = 1.2 1kg

φ 16 = 1.58kg

φ 18 = 2kg

φ 20 = 2.47kg.

22 = 3Kg

25 = 3.86Kg Theoretical weight calculation of steel Simple material name Theoretical weight W(kg/m) Flat steel, steel plate and steel strip w = 0.00785× width× thickness square steel w = 0.00785× side length 2 round steel, wire rod and steel wire w = 0.006 1.7× diameter 2 steel tube w = 0. 2.f value: general model and A model are 3.34, B model is 2.65, C model is 2.26..3.e value: general model and A model are 3.26, B model is 2.44, C model is 2.24.4. All length units are millimeters.

Question 6: How to calculate the weight of steel bars? Generally, the formula can be used, 0.006 17* rebar diameter * rebar diameter = rebar weight per meter of this diameter.

For example, the steel bar with a diameter of 10 has a weight of 0.00617 *10 *10 = 0.617 kg/m per meter.

Steel bars with a diameter of 20 weigh 0.006 17*20*20=2.468kg/m per meter.

Of course, if you are asking about steel bars, this should be based on steel bars, lap joints, bends, etc. If you have no practical experience, buy a "steelworker" and have a look.

Question 7: How to calculate the reinforcement La? The design is based on the formula in the concrete code.

During construction, this data is given directly according to the plan set or design.

Question 8: How to calculate the number of steel bars 3. 15 is calculated as 4.

When the net size of plane members is divided by the spacing size plus 1, the vertical distribution of reinforcement in the wall is reduced by 1.

Question 9: How to calculate the number of foundation reinforcement How to calculate the number of foundation reinforcement?

We set the horizontal direction of the independent foundation as X direction and the vertical direction as Y direction.

For example, the length in the X direction is 2400mm, and the reinforced room [mail protection]); The length in the Y direction is 2600mm, and [mail protection] is between steel bars). Concrete cover 40mm, calculate the number of steel bars in each direction? (More than 2500, 0.9 times, please deduct the reinforcement shortening. )

Solution: The length in X direction is: 2400 mm-40× 2 = 2320 mm; The length in the y direction is: 2600 mm-40× 2 = 2520 mm

The number of roots with a length of 2320mm in the X direction is: 2520 mm ÷ 200+ 1 = 14 (roots).

The number of roots with a length of 2520mm in the Y direction is 2320 mm ÷150+1=17 (roots). Note: When the length of the independent foundation slab is ≥2500mm, the reinforcement length of the slab can be 0.9 times that of the slab in the corresponding direction, except for external reinforcement. 15 (root) in 17 (root) can be taken as 2088 mm

A:

The number of roots with a length of 2320mm in the X direction is: 14 (roots).

The number of roots with a length of 2520mm in the Y direction is 17 (roots).