It takes about 6-7 minutes to boil 1L water in an electric kettle with a power of 800 W. ..

The heat required to boil 1L water is:

Q=c*m*t

=4.2* 10^3* 1*( 100-25)

=3 15000 joules

Among them:

C- specific heat capacity The specific heat capacity of water is 4.2 *10.3 joules per kilogram of Celsius.

M—— the mass unit is kilogram.

T—— the change of temperature (absolute value is taken whether the temperature rises or falls).

The calorific value of the electric kettle is approximately equal to Q (assuming the thermal efficiency is 100%).

pt=Q

Among them:

The unit of power is watts.

T- time unit is "seconds"

Get:

t=Q/p

=3 15000/800

=394 seconds

It takes 6 minutes and 40 seconds to boil about 1L of water in an electric kettle with a nominal power of 800 W. ..