Answer: The normal working resistance of the electric kettle is 44 Ω.
(2) The heat that water needs to absorb is Q absorption =c water m (t1-t0) = 4.2×103j/(kg? ℃)× 1kg×( 100℃-20℃)= 3.36× 10 5j。
Answer: The heat absorbed by water is 3.36× 105J.
(3) The total electricity consumption ranges from 3) 1 min to 60r: W = 60r 3000r/kW? h =0.02kW？ h=7.2× 1 0 4 J，
T = 1 min = 60 seconds
At this time, the total power consumption is ptotal = wtotal t = 7.2×104j60s =1200w.
Electric kettle works normally: p kettle =P amount =1100 w.
Because p is always > p pot,
So there are other appliances working in the circuit.