The pressure of water on the bottom of teapot F 1=p 1S pot = 1200Pax4× 10 negative cubic meter = 4.8n.
The pressure of the teapot on the desktop F2=G pot +G water =m pot g+m water g = 0.4kgx10n/kg+0.6kgx10n/kg =10n.
The pressure of the teapot on the desktop p2=F2/S pot = 10N/4× 10 negative cubic meter = ㎡=2.5x 10/0? protactinium