C stands for the first meeting place of two cars, and D stands for the second meeting place of two cars.
When they first met, the sum of the distances traveled by the two cars was equal to the distance between AB.
The AC of a car is equal to 32 kilometers.
The distance traveled by car B from the first meeting to the second meeting is CA+AD:
32+64 = 96 km
As can be seen from the figure,
When two cars meet at point C and drive to point D for the second time,
The sum of the distances traveled by two cars is equal to twice the distance between AB.
In other words, the distance traveled by the two cars is twice the distance they traveled when they first met.
When car B first met, the distance BC traveled was:
96 ÷ 2 = 48 kilometers
The distance between AB and BC is equal to AC+BC, that is:
32+48 = 80km