(0) Just remember that both sides on the left are positive numbers between 2 and 99, and the former is smaller than the latter.

(1) If I only know their sum, I don't know what these two numbers are. If I only know their products, I don't know what they are.

(2) But I know how to draw a conclusion. When I know the sum, I can't deduce these two coordinates just by knowing the product.

(3) However, if I know the product and I know that I only know the strong mineral of sum, I can draw a conclusion that I can't deduce these two coordinates just by knowing the product, so I can deduce these two coordinates.

(4) If I know the sum, I know only the product and the sum, and I can deduce these two coordinates, then I can also deduce these two coordinates.

Answer: Let two numbers be A.

According to (1),

(a)5 < a+b & lt； 197

(b) A and B cannot be prime numbers at the same time. If one of them is a prime number, then this prime number cannot be greater than 50.

From (2) and (b),

(c) If the integer N between 5 and 197 can be divided into the sum of two integers C and D, and both C and D are prime numbers or one of them is a prime number greater than 50, then N cannot be a+B ... so a+b can only be one of the following situations: 1 1 7.

When a+b is one of 1 1 in (c), the product ab can be known from (3).

(d) The product ab can only appear if the sum is unique, that is, if n=cd=ef and c+d≠e+f are all in the number of (C) 1 1, then n can't be ab. At this time, corresponding to each sum, there are the following number of product possibilities:

1 1:3; 17: 1; 23:3; 27:9; 29:9; 35: 1 1; 37:7; 4 1: 12; 47,51,53: more

Finally, from (4),

(e) The product ab corresponding to the sum of two coordinates A+B has only one possibility.

Then a+b= 17, ab=52, and a=4, b= 13 are obtained.