Current location - Health Preservation Learning Network - Slimming men and women - Let a and b be two real roots of the equation 4x2-4mx+m3 = 0. When m is what value, A 2+B 2 has the minimum value, so find the minimum value.
Let a and b be two real roots of the equation 4x2-4mx+m3 = 0. When m is what value, A 2+B 2 has the minimum value, so find the minimum value.
A and b are two real roots of the square of the equation 4x -4mx+m+2=0.

⊿= 16m？ -4*4(m+2)≥0，m≥2，m≤- 1

According to Vieta theorem: a+b=m, ab=(m+2)/4.

Answer? +b？ =(a+b)？ -2ab=m？ -(m+2)/2

=(m- 1/4)？ - 17/ 16

The symmetry axis m= 1/4, so when m=- 1,

Answer? +b？ The minimum value is 1/2.

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