B. the quality of the car is unknown. According to the kinetic energy expression Ek= 12mv2, it can be known that the kinetic energy Ek cannot be obtained when the car leaves the left slope. So, B is wrong.
C let the speed of the car leaving the left slope be v 1.
According to the uniform linear motion in the horizontal direction: d=v 1cosα? t…①
The vertical upward throwing action is Hm=(v 1sinα)22g…②.
With the vertical upward direction as the positive direction: -(h-H)=v 1sinα? t- 12gt 2③
Exercise time t and v 1 can be obtained from ② and ③, and the maximum height hm can be obtained from ②. So, C is correct.
D, according to the speed decomposition: tanα=vy 1vx, tanθ=vy2vx.
Since h > h and the vertical fractional velocity relation is vy 1 < vy2, α < θ, so d is correct.
So: CD.