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Super Fast Computing Hall of Fame -8 Rare
Super Fast Computing Hall of Fame -8 Rare

Selected time: 20 15-4- 10.

Selection level: 787.

Reason for selection: Rare, female, born in 1980s, stay-at-home mom, 82nd member of Super Memory Hall of Fame. After successfully climbing to the top of the Memory Hall of Fame on February 28th, she saw the wonderful abacus mental arithmetic and quick calculation performance of Mr. Xian, a gold medal lecturer in brain architecture education, and also saw the friends who insisted on learning in the quick calculation group, especially the lonely and enterprising friends in the group. I am very envious of the quick calculation results. In order to set an example for her daughter and to teach her children in the future, she immediately signed up for a quick calculation class and took the time to practice, and finally reached the level of 787 in two months. She wrote very detailed customs clearance methods and training experience, and shared her experience in YY in April 10. In order to thank her for her practice in the fast computing upgrade system and her help to everyone, she was specially selected as the eighth member of the Super Computing Hall of Fame and the third member of the Double Hall of Fame for Brain Architecture Education.

Ultra-fast calculation process of Sichuan rarity

First, introduce yourself.

I am rare, female, born after 80. I am an ordinary high school student. Because there is no one at home to take care of the children, the father of the child has to work to support the family, and I can only take care of the children alone. Since I began to contact with memory in late October of 20 14 10, I have taken time to practice. On February 24th, 20 15, the memory training software of the memory upgrade system was finally completed to level 77. On February 28th, I was elected as the 82nd member of the Super Memory Hall of Fame. Although I have entered the primary stage in memory, I think my speed calculation is not good. At the same time, I saw the wonderful abacus mental arithmetic and quick calculation performance of Mr. Xian, a gold medal lecturer in brain architecture education, and I admired the quick calculation achievements made by friends who insisted on learning, especially those who were lonely and enterprising in the group. Although I didn't go to college and I'm not good at everything, I hope my children can study easily and realize their lofty dreams in the future. The so-called parents will be a mirror for their children. Parents love to learn, and children will follow suit. With my own dream, I am honored to join the quick calculation group on February 3, 20 14, and follow the gold medal lecturer Mr. Xian step by step to the present.

Second, my learning process of fast calculation

Although I joined the quick calculation group in June+February of last year, I saw the problems in the quick calculation software at that time, from the addition and subtraction of 1 digit to the addition and subtraction of 5 digits, and three digits were multiplied by one digit. I found it difficult, so I left him alone. I didn't start practicing until 2065438+0565438+1October 24th. Now I will tell you about my quick calculation learning process according to the left and right order of the mobile phone version:

1.2 digit addition and subtraction: at first, I didn't think it was necessary to practice one digit. I started practicing from double digits, so I used the method of counting from the beginning to the end that Teacher Xian said. I thought double digits were relatively simple, but I practiced it many times. 65438+1On the afternoon of October 24th, the computer version of subtraction was cleared in 39 seconds, while the addition of two digits was passed in 39 seconds on the 25th of the next day.

2.3-digit addition and subtraction: Because I have time to train memory sticks and memory software, I don't have much time to practice quick calculation. I didn't take time to practice until February 28, so three digits are not as good as addition and subtraction of two digits. I always miss a few questions every time, but I didn't give up and continued training. I'm sure I can pass the exam. It took me a few days until March 3rd, and the mobile version got the best score of 79.

3.4-digit addition and subtraction: 4 digits is a bit difficult for an ordinary person. Since March 8th, I have taken time to practice at least 10 times every day. At that time, I also participated in the first quick scholarship, which really didn't stop for 7 days. I kept Mr. Xian's words in mind, "I can't believe this, I can't pass this time! Finally, in March of 14, the mobile version of 1 18 seconds was the best result.

4.5-digit addition and subtraction: practice began on April 3. I think I am familiar with the addition and subtraction of 2 and 3 digits, and I can also add and subtract 4 digits. I'm sure I can pass the addition and subtraction of five digits. I practiced for several times that morning, and I either pressed the wrong button or miscalculated, but I still had to ask a few questions to pass the exam. 10, the child is sleeping. I thought I wouldn't believe it. I couldn't figure it out. I started practicing again and really passed.

5. 1 bit multiplication and division method: after adding and subtracting 5 bits, of course, I want to solve the next level. 1 bit multiplication and division method is simple, but because there are many additions and subtractions recently, multiplication and division method has been treated as addition and subtraction for several times, and it takes 22 seconds at most after several times.

Multiplication and division of 6.2 digits: 1 digit, I can't help but think of multiplication and division of 2 digits, as long as I am familiar with addition and subtraction. I practiced 1 hour and passed the test with the mobile version 136 seconds.

7.2 Clear-cut: I did an exercise on June 25th, 65438. On that day, I posted an upgrade post on the forum with the best score of the computer version of 58 seconds. Although the score of 58 seconds is not good, it is already very happy for me. I am very grateful to the teachers of Memory Bar for developing such a good software, and to Mr. Xian for his careful explanation. For this level, I used the method taught by Mr. Xian to count, that is, this one plus one fell behind. As soon as we learn, we will remember the formula: this one doubles itself and falls behind by 5 to 1. If you practice too much, you will form conditioned radiation, and you will report it soon.

Example: 527×2=

0527× 2 ... Original formula

044 ... this one

10 1 ……………………………………………………………………………………………………………….

1054 products ......

Operation process:

1, the first five digits of the multiplicand are "full 5 1", and the first digit of the product is1;

0 of 2 and 5, the last bit of 2 "is less than 5, the last bit is 0, 0+0=0, and the second bit of the product is 0;

The original 3 plus 2 4, the last digit 7 is "full 5 1", the last digit 1, 4+ 1=5, and the third digit of the product is 5;

4 and 7 of the original 4, the last bit of the product is 4; ? ? The result of this question is: 1054.

7.5 Customs clearance: This customs clearance is also quite simple. Although simple, I practiced it several times on June 26th, 65438, which added up to about 2 hours, and only used the computer version for 58 seconds. The formula I use is: add zero to 1 write 5 in half (that is, a number itself is divided by 2), because I can easily see the operation process of a half number, such as 146×5: 146÷2=73, then adding 0 after the number 73 is1. If half of 147×5 and 147 are 73+0, then this number must be written as 5, so 147×5=735.

8.4 Qing: I'm also familiar with this and backward, so I'd better be conditioned. I took time to practice from March 1 1, and posted it the next day with the best score of 1 17 seconds in the mobile version. This: Even numbers are complements, and odd numbers are complements. That is to say, the original of 1 is 4, the original of 2 is 8, the original of 3 is 2, the original of 4 is 6, the original of 5 is 0, the original of 6 is 4, the original of 7 is 8, the original of 8 is 2, the original of 9 is 6, and the last one is 25 1, 5/2 and 75/3.

The flag of 9.8 is clear-cut: practice on March 24th, and pass the customs the same day. Before that, I had to go through the customs several times a day. You can get through customs with a bite of 4, and I believe you can get through 8, because 8 is twice as much as 4. Then this is complementary to each other, that is to say, the multiplicand 1 is 8, 2 is 6, 3 is 4, 4 is 2, 5 is 0, 6 is 8, 7 is 6, 8 is 4 and 9 is 2. Backward: pass 125 in 1, pass 25 in 2, pass 375 in 3, pass 5 in 4, pass 625 in 5 in 6 and pass 875 in 7. 1 Observation: When you meet 4, don't look back. Just 375 into 3, and 5 into 4 when you meet 5; Call 9, go straight to 875, and enter 7. 2-bit observation: look back when you meet 2, and enter1when you are over 25 years old; When you hit 7, look back If you hit 75 points, you will get 6 points. 3-bit observation: When encountering 1, 3, 6 and 8, we should pay attention to the difficulty of being backward in 8, so we need to flexibly use 2-bit observation and 3-bit observation. If 13 goes directly to 125 and enters 1, just look at two; When you meet 12, you need to look back and see if the position behind is all 5. If it is full of 5, you can enter 1, if it is less than 5, you can enter 0. It's the same when you meet 3, 6 and 8.

1 0.3: On March 30th, I used the mobile phone version to clear customs for 96 seconds, which took1hour. I think this is quite simple. I just need to recite this book and practice it a few times, and then I can go through customs. I will use Mr. Xian's method.

This: formula: the single digits of the multiplication formula.

1 2 3 4 5 6 7 8 9 multiplication

3 6 9 2 5 8 1 4 7 this one

Backward: Super 3 1, Super 61. Observation: If you encounter the numbers 1, 2, 4, 5, 7, 8, 9, you can directly judge the numbers, such as: 0, 1, 2 does not exceed 3 and does not carry; 4,5 super ternary1; Seven, eight and nine exceed six and become two. 2-bit or multi-bit observation: You need to read the cycle number of 3 or 6 until a different number appears to judge the decimal. When the multiplicand is 3 or 6 at a time, we compare it with 2-bit observation method; Two consecutive occurrences are compared with three digits, and so on. For example, 38×3, compared with 2-bit observation method, 38 > 33, so it is1; 664×3, compared with the 3-bit observation method, 664 < 666, 4 does not exceed 6, which is counted as more than 3 1, so the last bit is 1.

1 1.6' s clear explanation: On April 4th, I used the mobile version of 1 12 seconds to post the upgrade post, which took 40 minutes, just like Teacher Xian's.

This 6: formula: even myself, plus 5. Interpretation: even number is itself, odd number is the number obtained by adding 5 to itself.

1 2 3 4 5 6 7 8 9 multiplication

6 2 8 4 0 6 2 8 4 copies

Then backward: super 16 in 1, super 3 in 2, full 5 in 3, super 6 in 4, super 83 in 5, 1. Observation: For example, when you encounter the four numbers of 2, 4, 5, 7 and 9, you can directly judge the number of progress without looking back; 2 over 16 in1; 4 Super 3 into 2; 5 full 5 into 3; 7 super 6 into 4; 83 divided by 9 equals 5. Two-bit observation or multi-bit observation: when we encounter the four numbers 1, 3, 6, and 8, we should look back to see if the following numbers exceed their cycle numbers, and judge the carry according to whether they exceed them. For example, 1665, 1666 should not exceed the cycle number of 16, and should not be entered; 1667, 1668 exceeds the cycle number of 6. Enter 1. 333 1, 3333 cycle number does not exceed 3, enter1; 3334 and 3336 exceed cycle number 3, enter 2. 6662 and 6666 do not exceed 6 cycles, and enter 3; 6667 and 6669 exceed the cycle number of 6, enter 4. 833 1 and 8333 do not exceed 83 cycles, enter 4; 8334 and 8336 exceed 83 cycles, enter 5.

12.9, I also spent a few minutes on April 4th, and posted a mobile version of 1 14 second upgrade post.

This: Formula: 9 supplements. Any number is its own complement (the sum of two numbers equals ten, and these two numbers are each other's complement).

Multiplier? ? 1 2 3 4 5 6 7 8 9

It corresponds to 9 8 7 6 5 4 3 2 1.

The backward direction of 9: super 1 in 1, super 2 into 2, super 3 into 3, super 4 into 4, super 5 into 5, super 6 into 6, super 7 into 7, super 8 into 8 can be summarized as: super several into several.

When looking at the last digit of 9, after reading the first digit, the next digit is mainly greater than, less than or equal to.

The first number that determines the quantity. If the second digit is greater than the first digit, the decimal number is the first digit itself, for example, 23×9, and the next digit 3 of its 2 is greater than itself, so the carry is 2. If the second digit is less than the first digit, the decimal number is the first digit minus 1, such as 2 1×9, and the next digit of 2 1 is less than itself, so the decimal number is 2 minus 1. If the second place is equal to the first place, look at the third place, and then look down until you judge the size. The first few digits are all equal. If it is more than the first digit, it will be handled according to the first situation (carry itself is the first digit); When it is equal to or less than, it shall be handled according to the second case above, and the decimal number shall be the first place minus 1. For example, 22,223× 9 is regarded as greater than the first place, and carry 2; 22,222× 9 or 22,22 1 × 9, whichever is less than the first, and take1.

One-stop customs clearance 13.7: I passed the customs clearance after 9 stops on April 4th. Of course, I have memorized this song and the laggard. Although I only posted it in the mobile version 1 16 seconds, I am very happy, because I passed 697 one-stop and three-stop customs in one day, thanks to Teacher Xian's customs clearance cheats. Root of 7: Formula: Single digit of multiplication formula.

1 2 3 4 5 6 7 8 9 multiplication

7 4 1 8 5 2 9 6 3 this one

Backward direction of 7: the same digit as the first digit of the formula, exceeding 142857 1, exceeding 2857 14 to 2, exceeding 42857/kloc-0 to 3, and exceeding 57 1428 to 4. If the number of digits is 2 less than the first digit in the formula, the number of digits exceeds 7 14285 into 5, and the number of digits exceeds 857 142 into 6, 1. Observation: If you encounter three numbers: 3, 6 and 9, you can directly judge the number of digits. For example, if 3 exceeds 2857 14, it becomes 2; 6 Pass 57 1428 and enter 4; 9 super 857 142 into 6; 2-bit or multi-bit observation: In actual calculation, the number of cycles multiplied by 7 is rarely encountered, so it is most convenient to use 2-bit observation to determine backwardness. However, if the first two digits of the multiplicand appear 14, 28, 42, 57, 7 1 85, we will use the two-digit observation method to judge whether to carry.

Third, the comparison before and after study and its application in life

In the past, I always used a calculator or pen to calculate, and the calculation was not very fast, and I often made mistakes. Now that my quick calculation ability has improved, I'll start with my mouth. When I shop, I will first count the items I bought with my mouth to see if they are the same as the computer bill. If not, I will calculate who is wrong again.

Fourth, if you give it to beginners of fast calculation.

As long as the kung fu is deep and the iron bar is ground into a needle, it will always be difficult to learn at first. In fact, as long as you have confidence in yourself, I believe you can pass the exam. Although I know the answer clearly when typing, I make mistakes because of my quick hands or my slow speed because of my inexperience with the keyboard. This will definitely happen frequently. At this time, you need to stop and have a rest and practice next time. Dear friend, you can think of quick calculation as a game. Each mobile phone version has a small lock, and only one level can be completed before the next level can be played. You can also go to the forum to see the customs clearance skills of outstanding people. The mobile phone has a computer version and an Android version, and the computer version has a public service version and a registered version. You can practice the public service version at first, but if you want to practice more deeply, you might as well use the registered version because the registered version has more functions. In any case, you must keep practicing. I believe you will pass the exam soon, and your speed will be improved soon.

Verb (short for verb) My next plan.

Insist on practicing every day to strengthen your quick calculation ability, and apply it to your life, and take time to help more friends who learn quick calculation. I also recommend my friends and classmates to study together and cheer together.

Attachment: highlights of customs clearance experience

Addition and subtraction

Rare experience of double-digit addition and subtraction customs clearance in Sichuan

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Rare experience of three-digit addition and subtraction customs clearance in Sichuan

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Rare experience of 4-digit addition and subtraction customs clearance in Sichuan

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Sichuan's Rare Five-digit Customs Clearance Experience

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Clear in one mouthful

Experience Sichuan-Rare 2 Customs Clearance in One Go

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Rare experience of "five links" customs clearance in Sichuan

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Experiencing Sichuan —— Rare Four Levels in One Go

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Experiencing Sichuan —— Rare Eight Pass in One Go

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Sichuan's rare experience of "three customs clearance" and one customs clearance

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Experience of Sichuan Zhenqi No.6 Customs Clearance at One Time

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Sichuan experience-a rare 9-level customs clearance

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Experiencing Sichuan —— Rare 7 Pass in One Go

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Multiplication and division

Sichuan experience-a rare one-digit multiplication and division clearance

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Rare experience of double-digit multiplication and division in Sichuan

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For more tips on learning overspeed calculation, please refer to the Memory Bar Forum:

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