According to ohm's law, the current in the circuit:
I = u0r 0 = 1.5v 120ω= 0.0 125 a;
As can be seen from the image, when the pressure is 2000N, the corresponding resistance is R = 360ω.
Voltage across resistor r:
UR = IR = 0.0 125 a×360ω= 4.5V,
The currents everywhere in the series circuit are equal,
∴ Supply voltage:
u = U0+UR = 1.5V+4.5V = 6V;
(3) As can be seen from the image, the resistance R ′ = 600Ω when it is not impacted,
The total resistance in the series circuit is equal to the sum of the individual resistances,
∴ current in the circuit at this time:
I 1′= UR′+R0 = 6v 600ω+ 120ω= 1 120 a;
At this point, the voltmeter indicates:
u0′= I 1 r0 = 1 120 a× 120ω= 1V。
Answer: (1) The power supply voltage is 6V;
(2) When the equipment A is not impacted, the reading of the voltmeter is1v. ..