3x+y+0( 15-x-y)=33,
3x+y=33,
y=33-3x
X and y are positive integers or 0, and x+y ≤15;
①x = 9y = 6;
15-9-6=0;
②x = 10y = 3;
15- 10-3=2;
③ x= 1 1 y=0。
15- 1 1-0=4;
There are three situations: ①9 wins, 6 draws and 0 losses; ② 10 wins, 3 draws and 2 losses; ③ 1 1 win, 0 draw and 4 losses.
So the answer is: 3.