Second empty F2, d-r-9/16d-rr3/1ddRR-3/116, d-r-1/3dd. 2d drr 2/3× 1/2 = 1/3 ddrr 2/3× 1/4 = 1/6 ddrr。 Remove the last ddrr for 1/2 ÷ (1/2+. 5× 1/4)= 7/ 10 ddRR(2/5× 1/2)= 1/5 DDRR 2/5× 1/4 = 1/65438+。
Just calculate this problem step by step.
2) For chromosomes with only one pollen per pair, there are two possibilities. So 2× 2× 2×''''' is the n power of 2.
3) Inoculation experiment of rust-resistant gene rust fungus.