1/√(n^2+ 1)+ 1/√(n^2+2)+....+ 1/√(n^2+n)<； n/√(n^2+ 1)

1/√(n^2+ 1)+ 1/√(n^2+2)+....+ 1/√(n^2+n)>； n/√(n^2+n)

That is,1√ (N2+1)+1√ (N2+2)+...+1√ (N2+n) in n/√ (N2+n)

1/√( 1+ 1/n)& lt； 1/√(n^2+ 1)+ 1/√(n^2+2)+....+ 1/√(n^2+n)<； 1/√( 1+ 1/n^2)

In n- >, n/√ (N2+n) =1√ (1+1/n); ∝ Yes 1

In n- >, n/√ (N2+1) =1√ (1+1/N2); ∝ Also 1

Then1/√ (N2+1)+1√ (N2+2)+...+1√ (N2+n) is in it, and in n->; Of course it is also 1.

How can it be 0?