Current location - Health Preservation Learning Network - Health preserving class - Nannan saw a piece of material in the data, which was the result of the experiment of measuring the resistance of a small bulb with a rated voltage of 2.5V by the students of physics department of a u
Nannan saw a piece of material in the data, which was the result of the experiment of measuring the resistance of a small bulb with a rated voltage of 2.5V by the students of physics department of a u
Nannan saw a piece of material in the data, which was the result of the experiment of measuring the resistance of a small bulb with a rated voltage of 2.5V by the students of physics department of a university. (1)① Draw points according to the data in the table and connect them with smooth curves, as shown in the figure:

② According to the data in the table, when the voltage U=2.5V, the current is 0.2A, so R = UI = 2.5V0.2A =12.5Ω;

(2)① Connect the objects according to the circuit diagram, and the power supply consists of two dry batteries, so the range of 0 ~ 3v can be selected;

The sliding rheostat has been connected to the lower terminal and then to the upper terminal;

The ammeter is connected in series with the bulb, and the range of 0 ~ 0.6a is optional, as shown in the following figure:

(2) When connecting the circuit, the switch should be turned off;

The voltmeter indicates zero, and the ammeter indicates increase, which is caused by the short circuit of the bulb;

③ According to the first set of data, when the current in the circuit is 0.02A, the voltmeter indicates 0.2V,

At this time, the resistance of bulb R lamp =U lamp I=3V? 0.2v0.02a =140Ω, and the maximum resistance of sliding rheostat is 50Ω, so the above experiment cannot be completed.

So the answer is: (1)① See the above picture; ②0.2; 12.5; (2)① See the above figure; 2 disconnect; Short circuit of bulb; ③ No; When the voltage is 0.2V and the current is 0.02A, the resistance of the sliding rheostat should be140Ω, and its maximum resistance is 50Ω, so it cannot be completed.