② According to the data in the table, when the voltage U=2.5V, the current is 0.2A, so R = UI = 2.5V0.2A =12.5Ω;
(2)① Connect the objects according to the circuit diagram, and the power supply consists of two dry batteries, so the range of 0 ~ 3v can be selected;
The sliding rheostat has been connected to the lower terminal and then to the upper terminal;
The ammeter is connected in series with the bulb, and the range of 0 ~ 0.6a is optional, as shown in the following figure:
(2) When connecting the circuit, the switch should be turned off;
The voltmeter indicates zero, and the ammeter indicates increase, which is caused by the short circuit of the bulb;
③ According to the first set of data, when the current in the circuit is 0.02A, the voltmeter indicates 0.2V,
At this time, the resistance of bulb R lamp =U lamp I=3V? 0.2v0.02a =140Ω, and the maximum resistance of sliding rheostat is 50Ω, so the above experiment cannot be completed.
So the answer is: (1)① See the above picture; ②0.2; 12.5; (2)① See the above figure; 2 disconnect; Short circuit of bulb; ③ No; When the voltage is 0.2V and the current is 0.02A, the resistance of the sliding rheostat should be140Ω, and its maximum resistance is 50Ω, so it cannot be completed.