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When did the earthquake in Japan exercise?
Solution: (1) Let the resolution function of y 1 and x be Y 1 = KX+B (k > 0).

Get it according to the meaning of the question.

b=0.220k+b= 1.2

Solution:

k=0.05b=0.2

The relationship between y 1 and x is y 1=0.05x+0.2.

(2) According to the meaning of the question, y1+y2 = 0.05x+0.2+0.005x+0.3 = 3.8, and the solution is x=60.

The company's total sales in May was 60 units.

(3) Suppose that P sets of Type B equipment were sold in May, then 60 sets of Type C equipment (60-t-p) were sold.

Then 0.9t+1.2p+1.1(60-t-p) = 64.

The solution is p=2t-20.

∴w= 1.2t+ 1.6(2t-20)+ 1.3(60-t-2t+20)-64-3.8

That is, the functional relationship between w and t is: w = 0.5t+4.2 (14 ≤ t ≤ 24);

(4) according to the meaning of the problem, there are

t≥8

2t-20≥8

60-t-2t+20≥8

The solution is 14≤t≤24.

And ∵t is a positive integer.

∴t Up to 24

∫w is a linear function about t, and from (3), w increases with the increase of t 。

∴ When t=24 (units), W max =0.5×24+4.2= 16.2 (ten thousand yuan)

The maximum amount of the company's donation to the disaster area this time is162,000 yuan.