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( 1)G = mg = 20k G× 10N/kg = 200n;

(2)∵ When not pulled, the pressure of the counterweight on the ground is f = g = 200 n;

∴ pressure on the ground p=FS=200N4× 10? 3 m2 = 5× 104 pa;

(3) useful work done by pulling force:

w = Gh = 200n×0.4m = 80J;

(4) The power of pulling force P = WT = 80J2S = 40W.

Answer: (1) The gravity on the counterweight is 200 N;

(2) When not pulled, the pressure of the counterweight on the ground is 5×104 Pa;

(3) During the pulling process, the work done by the pulling force on the counterweight is 80J;;

(4) In the process of traction, the traction power is 40W. ..