Judging from the title: the block of wood remains the same. According to the two-force equilibrium condition, it is proved that the buoyancy of F block is -G block = the pulling force of F rope P water = 1× 10? 0? 6kg|m？ 0? 6 V line =5dm? 0? 6=0.005m？ 0? 6 P wood =0.5× 10? 0? 6kg|m？ 0? 6 g= 10N/kgF block buoyancy =P water *V row g=50N G block =P wood v row G = 25nf rope tension = F block buoyancy -G block = 50n-25n = 25n.