Eg is a tangent,

∴∠KGE+∠OGA=90。

∵CD⊥AB，

∴∠AKH+∠OAG=90，

OA = OG，

∴∠OGA=∠OAG，

∴∠KGE=∠AKH=∠GKE，

∴KE=GE.

(2)KG2=KD？ Ge. The reason for this is the following：

Connect GD as shown in figure 2.

∫AC∑EF，

∴∠C=∠E.

∠∠C =∠AGD，

∴∠KGD=∠E.

Also: from (1) ∠KGE=∠GKE

∴△GKD∽△EGK，

∴KGGE=KDKG, that is, KG2=KD? Ge;

(3) Connect OG and OC, as shown in Figure 3.

SinE=sin∠ACH=35, let AH=3t, then AC=5t, CH=4t,

∵ke=ge,ac∥ef,∴ck=ac=5t,∴hk=ck-ch=t.

In Rt△AHK, we get AH2+HK2=AK2 according to Pythagorean theorem.

That is, (3t)2+t=2. =(25)2, the solution is t = 2.

Let ⊙O radius be r, in Rt△OCH, OC=r, OH=r-3t, CH=4t,

From Pythagorean Theorem: OH2+CH2=OC2,

That is, (r-3t)2+(4t)2=r2, and the solution is r = 256t = 2526.

∵EF is tangent, ∴△OGF is right triangle,

In Rt△OGF, OG=r=2526, tan∠OFG=tan∠CAH=CHAH=43.

∴FG=OGtan∠OFG=25: I praised it and stepped on it. What's your comment on this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Lawyer recommendation service: If your problem is not solved, please describe your problem in detail and provide free professional consultation through Baidu Legal Pro. Other similar problems 2022-11-21are known: As shown in the figure, AB is the diameter ⊙O, and the tangent BF of ⊙O intersects the extension line of the chord AD at the point F2065438+. Chengdu) as shown in the figure, AB is the diameter ⊙O, the chord CD⊥AB is in H, and the tangent ⊙O passes through a point E on the extension line of CD and the extension line is in F. The tangent point is 21201-08-18ab is a circle. Wuhan simulation) as shown in the figure, AB is the diameter ⊙O, the chord CD⊥AB is at point H, and the tangent of as ⊙O passing through point B intersects with the extension line of AD at point F (1) Verification102013-05-/kloc-0. Chengdu), as shown in the figure, the diameter of AB is ⊙O, and the chord CD⊥AB is in H. It is known that AB crosses a point E on the extension line of CD ⊙112012-05-15. Fuxin) As shown in the figure, AB is the diameter ⊙O, CD is the chord ⊙O, and the extension lines of AB and CD intersect at point E. If AB=2DE and ∠ e = 18, then ∠AOC6 is recommended to you: F.context('cmsRight') is especially recommended. [{ ' URL ':'/d 0 1373 f 082025 AAF 5 1 1aa 256 e 9 edab 64034 f 1a 07？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId':'A24KA00562 '，}，{ ' URL ':/s？ word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian '，' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}])； The price of electric cars has dropped many times. Is the quality guaranteed? What impact will the "network toilet" have? Is Huaqiang North's second-hand mobile phone reliable? Why is the cost of cancer treatment getting higher and higher? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "，" url":"/hm.js？ 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "； var s = document . getelementsbytagname(" script ")[0]； s.parentNode.insertBefore(hm，s)； })(); window . TT = 17 1969464 1；